I'll just put the formula with a capital $D$ so that $a_n = $ the value on day $n = a + (n-1)D$ where we have $D= d+1$ and $a=A$. And variables are just notation we could use anything. And $d=$ the amount changed each day then $a_n = $ the value on day $n = a+ (n-1)d$.īut as the variable $d$ is given to mean something arbitrarily different we have to use a different variable in our formula. Your formula for an arithmetic sequence seems to be if $a = $ Value of first day. If you are looking to plug numbers into the formula don't use $d$ for both $d$ and $d+1$. Something is telling me its a problem that I can use system of linear equation to find value of d.
Aplus math coach how to#
My understanding is that the formula be written asĪt this point I don't know how to find the answer of question b. Given that Yi and Xin will run for the same length of time on day 14, She will then increase her running time by (2d-1) minutes each day. She will then increase her running time by (d+1) minutes each day, where d is a constant.Ī) Show that on day 14, Xin will run for ```(A + 13d +13) minutes```Īt this point I think I understand that I can write formula asĪ+(n-1)d where a = A and d=(d+1) and n=14Ģ) Yi has also been given a 14 day training schedule by her coach. Xin will fun for A minutes on day 1, where A is a constant. Please someone talk me thru a baby step on this question please?ġ) Xin has been given a 14 day training schedule by her coach.
Aplus math coach series#
Taking a calculus class and trying to solve a series and sequence word problem but I am struggling on the easiest problem.
0 kommentar(er)
